What is factor x^3-7x^2+11x-5 ?

The solution to factor x^3-7x^2+11x-5 is (x-1)^2(x-5)

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factor x^3-7x^2+11x-5

factor

x^{3} - 7 x^{2} + 11 x - 5

(x - 1)^{2} (x - 5)

Solution steps

x^{3} - 7 x^{2} + 11 x - 5

Use the rational root theorem

= (x - 1) \frac{x ^{3} - 7 x ^{2} + 11 x - 5}{x - 1}

\frac{x ^{3} - 7 x ^{2} + 11 x - 5}{x - 1} = x^{2} - 6 x + 5

= (x - 1) (x^{2} - 6 x + 5)

Factor

x^{2} - 6 x + 5 : (x - 1) (x - 5)

= (x - 1) (x - 1) (x - 5)

Apply exponent rule:

aa = a^{2}

(x - 1) (x - 1) = (x - 1)^{2}

= (x - 1)^{2} (x - 5)

p + 12 = 67

45 m^{3} n - 5 mn

27 y^{3} - 125

x^{2} - \frac{3}{4} x + \frac{9}{64}

8 x^{2} - 30 x + 18

What is factor x^3-7x^2+11x-5 ?
The solution to factor x^3-7x^2+11x-5 is (x-1)^2(x-5)