What are the solutions to the equation s^2+10s+21=0 ?

The solutions to the equation s^2+10s+21=0 are s=-3,s=-7

Find the zeros of s^2+10s+21=0

The zeros of s^2+10s+21=0 are s=-3,s=-7

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s^{2} + 10 s + 21 = 0

s = - 3, s = - 7

Solution steps

s^{2} + 10 s + 21 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 21 = 4

s_{1, 2} = \frac{- 10 \pm 4}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 10 + 4}{2 \cdot 1}, s_{2} = \frac{- 10 - 4}{2 \cdot 1}

s = \frac{- 10 + 4}{2 \cdot 1} : - 3

s = \frac{- 10 - 4}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

s = - 3, s = - 7

\frac{( \frac{1}{2} ) ^{2}}{2}

0.2 5^{2}

lo g_{12} (3) + 2 lo g_{12} (2)

3^{2}

c (2) = - 6 (- \frac{1}{3})^{2 - 1}

What are the solutions to the equation s^2+10s+21=0 ?
The solutions to the equation s^2+10s+21=0 are s=-3,s=-7
Find the zeros of s^2+10s+21=0
The zeros of s^2+10s+21=0 are s=-3,s=-7