What are the solutions to the equation 5x^2+6=56 ?

The solutions to the equation 5x^2+6=56 are x=sqrt(10),x=-sqrt(10)

Find the zeros of 5x^2+6=56

The zeros of 5x^2+6=56 are x=sqrt(10),x=-sqrt(10)

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5 x^{2} + 6 = 56

x = 10, x = - 10

Decimal Notation

x = 3.16227 \dots, x = - 3.16227 \dots

Solution steps

5 x^{2} + 6 = 56

Move

6

to the right side

5 x^{2} = 50

Divide both sides by

5

x^{2} = 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 10, x = - 10

(- \frac{5}{3})^{3}

\frac{x - 2}{x + 6} \geq 0

a^{8} + 8 a^{4} b^{4} + 16 b^{8}

2 - \frac{2}{3}

42

What are the solutions to the equation 5x^2+6=56 ?
The solutions to the equation 5x^2+6=56 are x=sqrt(10),x=-sqrt(10)
Find the zeros of 5x^2+6=56
The zeros of 5x^2+6=56 are x=sqrt(10),x=-sqrt(10)