What is the answer to (2x(3-4x)-(x-2))/5 = 1/(2[\frac{x+3-(x-1)){2}]} ?

The answer to (2x(3-4x)-(x-2))/5 = 1/(2[\frac{x+3-(x-1)){2}]} is x=-1/8 ,x= 3/4

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(2x(3-4x)-(x-2))/5 = 1/(2[\frac{x+3-(x-1)){2}]}

\frac{2 x ( 3 - 4 x ) - ( x - 2 )}{5} = \frac{1}{2 [ \frac{x + 3 - ( x - 1 )}{2} ]}

x = - \frac{1}{8}, x = \frac{3}{4}

Decimal Notation

x = - 0.125, x = 0.75

Solution steps

\frac{2 x ( 3 - 4 x ) - ( x - 2 )}{5} = \frac{1}{2 [ \frac{x + 3 - ( x - 1 )}{2} ]}

Cross multiply

(- 8 x^{2} + 5 x + 2) \cdot 4 = 5

Solve

(- 8 x^{2} + 5 x + 2) \cdot 4 = 5 : x = - \frac{1}{8}, x = \frac{3}{4}

x = - \frac{1}{8}, x = \frac{3}{4}

\frac{2 π}{\frac{5}{2}}

5 m - 7 \geq m + 17

∣ 6 x - 2 ∣ + 8 = 8

2 (x + 1) - 3 (x - 2) = x + 6

600 = 1.373 x + x

What is the answer to (2x(3-4x)-(x-2))/5 = 1/(2[\frac{x+3-(x-1)){2}]} ?
The answer to (2x(3-4x)-(x-2))/5 = 1/(2[\frac{x+3-(x-1)){2}]} is x=-1/8 ,x= 3/4
Solve for x: (2x(3-4x)-(x-2))/5 = 1/(2[\frac{x+3-(x-1)){2}]}
The solution is x=-1/8 ,x= 3/4