What are the solutions to the equation 2^2+8^2=c^2 ?

The solutions to the equation 2^2+8^2=c^2 are c=2sqrt(17),c=-2sqrt(17)

Find the zeros of 2^2+8^2=c^2

The zeros of 2^2+8^2=c^2 are c=2sqrt(17),c=-2sqrt(17)

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2^{2} + 8^{2} = c^{2}

c = 217, c = - 217

Decimal Notation

c = 8.24621 \dots, c = - 8.24621 \dots

Solution steps

2^{2} + 8^{2} = c^{2}

Switch sides

c^{2} = 2^{2} + 8^{2}

Simplify

2^{2} + 8^{2} : 68

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 68, c = - 68

68 = 217

- 68 = - 217

c = 217, c = - 217

(x - 1)^{2} = 7

x^{2} + 8 x y + 16 y^{2}

x^{2 - 8 x + 15}

11 w^{3} - 9 w^{2} + 11 w - 9

- x^{2} - 3 x + 4

What are the solutions to the equation 2^2+8^2=c^2 ?
The solutions to the equation 2^2+8^2=c^2 are c=2sqrt(17),c=-2sqrt(17)
Find the zeros of 2^2+8^2=c^2
The zeros of 2^2+8^2=c^2 are c=2sqrt(17),c=-2sqrt(17)