What are the solutions to the equation 9x^2+2x=2 ?

The solutions to the equation 9x^2+2x=2 are x=(-1+sqrt(19))/9 ,x=-(1+sqrt(19))/9

Find the zeros of 9x^2+2x=2

The zeros of 9x^2+2x=2 are x=(-1+sqrt(19))/9 ,x=-(1+sqrt(19))/9

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9 x^{2} + 2 x = 2

x = \frac{- 1 + 19}{9}, x = - \frac{1 + 19}{9}

Decimal Notation

x = 0.37321 \dots, x = - 0.59543 \dots

Solution steps

9 x^{2} + 2 x = 2

Move

2

to the left side

9 x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

2^{2} - 4 \cdot 9 (- 2) = 219

x_{1, 2} = \frac{- 2 \pm 2 19}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 2 + 2 19}{2 \cdot 9}, x_{2} = \frac{- 2 - 2 19}{2 \cdot 9}

x = \frac{- 2 + 2 19}{2 \cdot 9} : \frac{- 1 + 19}{9}

x = \frac{- 2 - 2 19}{2 \cdot 9} : - \frac{1 + 19}{9}

The solutions to the quadratic equation are:

x = \frac{- 1 + 19}{9}, x = - \frac{1 + 19}{9}

7 x^{2} - 11 x - 6 = 0

∣ x + 4 ∣ \geq 5

63 \cdot 2

\frac{x - 1}{x + 1} \leq \frac{2 x - 5}{x - 1}

7 x^{2} + 2 x + 3 = 0

What are the solutions to the equation 9x^2+2x=2 ?
The solutions to the equation 9x^2+2x=2 are x=(-1+sqrt(19))/9 ,x=-(1+sqrt(19))/9
Find the zeros of 9x^2+2x=2
The zeros of 9x^2+2x=2 are x=(-1+sqrt(19))/9 ,x=-(1+sqrt(19))/9