What are the solutions to the equation y^2=289 ?

The solutions to the equation y^2=289 are y=17,y=-17

Find the zeros of y^2=289

The zeros of y^2=289 are y=17,y=-17

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y^{2} = 289

y = 17, y = - 17

Solution steps

y^{2} = 289

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 289, y = - 289

289 = 17

- 289 = - 17

y = 17, y = - 17

5 x^{2} - 13 x + 8

x = (- 5 - 4)^{2}

∣ 5 x - 8 ∣ < 10

21 y^{2} + 10 y - 16

What are the solutions to the equation y^2=289 ?
The solutions to the equation y^2=289 are y=17,y=-17
Find the zeros of y^2=289
The zeros of y^2=289 are y=17,y=-17