What are the solutions to the equation 6x^2=-12x-2 ?

The solutions to the equation 6x^2=-12x-2 are x=(-3+sqrt(6))/3 ,x=-(3+sqrt(6))/3

Find the zeros of 6x^2=-12x-2

The zeros of 6x^2=-12x-2 are x=(-3+sqrt(6))/3 ,x=-(3+sqrt(6))/3

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6 x^{2} = - 12 x - 2

x = \frac{- 3 + 6}{3}, x = - \frac{3 + 6}{3}

Decimal Notation

x = - 0.18350 \dots, x = - 1.81649 \dots

Solution steps

6 x^{2} = - 12 x - 2

Move

2

to the left side

6 x^{2} + 2 = - 12 x

Move

12 x

to the left side

6 x^{2} + 2 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} + 12 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

1 2^{2} - 4 \cdot 6 \cdot 2 = 46

x_{1, 2} = \frac{- 12 \pm 4 6}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 12 + 4 6}{2 \cdot 6}, x_{2} = \frac{- 12 - 4 6}{2 \cdot 6}

x = \frac{- 12 + 4 6}{2 \cdot 6} : \frac{- 3 + 6}{3}

x = \frac{- 12 - 4 6}{2 \cdot 6} : - \frac{3 + 6}{3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 6}{3}, x = - \frac{3 + 6}{3}

(\frac{1}{x})^{6}

9.8 \cdot 3

\frac{1}{2} e^{- \frac{8}{2}}

4 (w - 6) = 3 (w + 1)

- 6 x - 32 = - 8 x + 32

What are the solutions to the equation 6x^2=-12x-2 ?
The solutions to the equation 6x^2=-12x-2 are x=(-3+sqrt(6))/3 ,x=-(3+sqrt(6))/3
Find the zeros of 6x^2=-12x-2
The zeros of 6x^2=-12x-2 are x=(-3+sqrt(6))/3 ,x=-(3+sqrt(6))/3