What is 26x-3<= 23x+4<= 15x+10 ?

The solution to 26x-3<= 23x+4<= 15x+10 is x<= 3/4

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26x-3<= 23x+4<= 15x+10

26 x - 3 \leq 23 x + 4 \leq 15 x + 10

x \leq \frac{3}{4}

Interval Notation

(- \infty, \frac{3}{4}]

Decimal Notation

x \leq 0.75

Solution steps

26 x - 3 \leq 23 x + 4 \leq 15 x + 10

a \leq u \leq b

then

a \leq u and u \leq b

26 x - 3 \leq 23 x + 4 and 23 x + 4 \leq 15 x + 10

26 x - 3 \leq 23 x + 4 : x \leq \frac{7}{3}

23 x + 4 \leq 15 x + 10 : x \leq \frac{3}{4}

Combine the intervals

x \leq \frac{7}{3} and x \leq \frac{3}{4}

Merge Overlapping Intervals

x \leq \frac{3}{4}

\frac{7}{5} = \frac{x}{3}

3 (x + 2) (x - 2) = 5 x

\frac{1}{2} \cdot 6 \cdot 8

- 3 \leq \frac{2 - 2 x}{2} \leq 3

x^{5} + 2 x^{3} + x

What is 26x-3<= 23x+4<= 15x+10 ?
The solution to 26x-3<= 23x+4<= 15x+10 is x<= 3/4