What are the solutions to the equation 0=19.23x+3.25x^2 ?

The solutions to the equation 0=19.23x+3.25x^2 are x=0,x=-1923/325

Find the zeros of 0=19.23x+3.25x^2

The zeros of 0=19.23x+3.25x^2 are x=0,x=-1923/325

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0 = 19.23 x + 3.25 x^{2}

x = 0, x = - \frac{1923}{325}

Decimal Notation

x = 0, x = - 5.91692 \dots

Solution steps

0 = 19.23 x + 3.25 x^{2}

Multiply both sides by

100

0 = 1923 x + 325 x^{2}

Switch sides

1923 x + 325 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

325 x^{2} + 1923 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1923 \pm 192 3 ^{2} - 4 \cdot 325 \cdot 0}{2 \cdot 325}

192 3^{2} - 4 \cdot 325 \cdot 0 = 1923

x_{1, 2} = \frac{- 1923 \pm 1923}{2 \cdot 325}

Separate the solutions

x_{1} = \frac{- 1923 + 1923}{2 \cdot 325}, x_{2} = \frac{- 1923 - 1923}{2 \cdot 325}

x = \frac{- 1923 + 1923}{2 \cdot 325} : 0

x = \frac{- 1923 - 1923}{2 \cdot 325} : - \frac{1923}{325}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1923}{325}

- \frac{\frac{8}{7}}{( - \frac{10}{9} )}

x^{2} < x + 6

m^{2} - 6 m + 8 > 0

m^{2} - 2 m - 168

s^{2} + 4 s + 4

What are the solutions to the equation 0=19.23x+3.25x^2 ?
The solutions to the equation 0=19.23x+3.25x^2 are x=0,x=-1923/325
Find the zeros of 0=19.23x+3.25x^2
The zeros of 0=19.23x+3.25x^2 are x=0,x=-1923/325