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Popular >

1>= |7x-1|>3

Solution

1 \geq ∣ 7 x - 1 ∣ > 3

Solution

No Solution

Solution steps

1 \geq ∣ 7 x - 1 ∣ > 3

If

a \geq u > b

then

a \geq u and u > b

1 \geq ∣ 7 x - 1 ∣ and ∣ 7 x - 1 ∣ > 3

1 \geq ∣ 7 x - 1 ∣ : 0 \leq x \leq \frac{2}{7}

∣ 7 x - 1 ∣ > 3 : x < - \frac{2}{7} or x > \frac{4}{7}

Combine the intervals

0 \leq x \leq \frac{2}{7} and (x < - \frac{2}{7} or x > \frac{4}{7})

Merge Overlapping Intervals

No Solution

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\frac{2}{- 4}

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((x + h)^{2} - 2 (x + h)^{3}) - (x^{2} - 2 x^{3})

∣ x + 3 ∣ + ∣ x - 2 ∣ = 7

Frequently Asked Questions (FAQ)

What is 1>= |7x-1|>3 ?
The solution to 1>= |7x-1|>3 is No Solution