What are the solutions to the equation z^2+3z-54=0 ?

The solutions to the equation z^2+3z-54=0 are z=6,z=-9

Find the zeros of z^2+3z-54=0

The zeros of z^2+3z-54=0 are z=6,z=-9

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z^{2} + 3 z - 54 = 0

z = 6, z = - 9

Solution steps

z^{2} + 3 z - 54 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 54) = 15

z_{1, 2} = \frac{- 3 \pm 15}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 3 + 15}{2 \cdot 1}, z_{2} = \frac{- 3 - 15}{2 \cdot 1}

z = \frac{- 3 + 15}{2 \cdot 1} : 6

z = \frac{- 3 - 15}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

z = 6, z = - 9

8 n = n^{2} + 15

(3 x y^{5})^{5}

\frac{2}{7} (x - 3) - \frac{2}{3} = \frac{1}{3} (2 x - 6)

8 (4 u - 1) - 12 u = 11 (2 u - 6)

15 y + 32 = 2 (10 y - 7) - 5 y + 46

What are the solutions to the equation z^2+3z-54=0 ?
The solutions to the equation z^2+3z-54=0 are z=6,z=-9
Find the zeros of z^2+3z-54=0
The zeros of z^2+3z-54=0 are z=6,z=-9