What are the solutions to the equation (x-9)(x+4)=0 ?

The solutions to the equation (x-9)(x+4)=0 are x=9,x=-4

Find the zeros of (x-9)(x+4)=0

The zeros of (x-9)(x+4)=0 are x=9,x=-4

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(x - 9) (x + 4) = 0

x = 9, x = - 4

Solution steps

(x - 9) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 9 = 0 or x + 4 = 0

Solve

x - 9 = 0 : x = 9

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = 9, x = - 4

\frac{3 x}{4 y ^{2}} - \frac{y}{10 x}

0 = 3 x^{2} + 8 x - 3

\frac{x + 3}{4} = \frac{x + 4}{5}

7^{2 n} \geq 5 2^{4 n + 3}

x - 6 > \frac{2}{x}

What are the solutions to the equation (x-9)(x+4)=0 ?
The solutions to the equation (x-9)(x+4)=0 are x=9,x=-4
Find the zeros of (x-9)(x+4)=0
The zeros of (x-9)(x+4)=0 are x=9,x=-4