What are the solutions to the equation 2x^2-4x-70=0 ?

The solutions to the equation 2x^2-4x-70=0 are x=7,x=-5

Find the zeros of 2x^2-4x-70=0

The zeros of 2x^2-4x-70=0 are x=7,x=-5

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2 x^{2} - 4 x - 70 = 0

x = 7, x = - 5

Solution steps

2 x^{2} - 4 x - 70 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 70 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 70) = 24

x_{1, 2} = \frac{- ( - 4 ) \pm 24}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 24}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 24}{2 \cdot 2}

x = \frac{- ( - 4 ) + 24}{2 \cdot 2} : 7

x = \frac{- ( - 4 ) - 24}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = 7, x = - 5

x^{2 - x + 1}

(x - 1) (x + 4) (4 - x) < 0

7 x^{2} = 112

x^{2} + 3 x y - 18 y^{2}

15 < - \frac{2}{3} (x - 18)

What are the solutions to the equation 2x^2-4x-70=0 ?
The solutions to the equation 2x^2-4x-70=0 are x=7,x=-5
Find the zeros of 2x^2-4x-70=0
The zeros of 2x^2-4x-70=0 are x=7,x=-5