What are the solutions to the equation -x^2-4x+5=0 ?

The solutions to the equation -x^2-4x+5=0 are x=-5,x=1

Find the zeros of -x^2-4x+5=0

The zeros of -x^2-4x+5=0 are x=-5,x=1

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- x^{2} - 4 x + 5 = 0

x = - 5, x = 1

Solution steps

- x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) \cdot 5}{2 ( - 1 )}

(- 4)^{2} - 4 (- 1) \cdot 5 = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 ( - 1 )}, x_{2} = \frac{- ( - 4 ) - 6}{2 ( - 1 )}

x = \frac{- ( - 4 ) + 6}{2 ( - 1 )} : - 5

x = \frac{- ( - 4 ) - 6}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = - 5, x = 1

∣ x + 6 ∣ = 9

3 x^{2} - 4 x y - 4 y^{2}

(7 x - 2)^{2} = 4

∣ x - 2 ∣ \geq 5

- 4 m \geq - 4

What are the solutions to the equation -x^2-4x+5=0 ?
The solutions to the equation -x^2-4x+5=0 are x=-5,x=1
Find the zeros of -x^2-4x+5=0
The zeros of -x^2-4x+5=0 are x=-5,x=1