What are the solutions to the equation -4x^2-5x=-2 ?

The solutions to the equation -4x^2-5x=-2 are x=-(5+sqrt(57))/8 ,x=(sqrt(57)-5)/8

Find the zeros of -4x^2-5x=-2

The zeros of -4x^2-5x=-2 are x=-(5+sqrt(57))/8 ,x=(sqrt(57)-5)/8

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- 4 x^{2} - 5 x = - 2

x = - \frac{5 + 57}{8}, x = \frac{57 - 5}{8}

Solution steps

- 4 x^{2} - 5 x = - 2

Move

2

to the left side

- 4 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 4 ) \cdot 2}{2 ( - 4 )}

(- 5)^{2} - 4 (- 4) \cdot 2 = 57

x_{1, 2} = \frac{- ( - 5 ) \pm 57}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 57}{2 ( - 4 )}, x_{2} = \frac{- ( - 5 ) - 57}{2 ( - 4 )}

x = \frac{- ( - 5 ) + 57}{2 ( - 4 )} : - \frac{5 + 57}{8}

x = \frac{- ( - 5 ) - 57}{2 ( - 4 )} : \frac{57 - 5}{8}

The solutions to the quadratic equation are:

x = - \frac{5 + 57}{8}, x = \frac{57 - 5}{8}

\frac{( x ^{3} y ^{5} z ^{5} ) ^{6}}{( x ^{5} y ^{5} z ) ^{5}}

∣ v - 455 ∣ < 23

(\frac{3 x ^{5} y ^{3}}{x ^{3} y ^{6}})^{4}

\frac{9 + ( - 3 )}{2}

- x^{2} + 6 x + 3 = 0

What are the solutions to the equation -4x^2-5x=-2 ?
The solutions to the equation -4x^2-5x=-2 are x=-(5+sqrt(57))/8 ,x=(sqrt(57)-5)/8
Find the zeros of -4x^2-5x=-2
The zeros of -4x^2-5x=-2 are x=-(5+sqrt(57))/8 ,x=(sqrt(57)-5)/8