What are the solutions to the equation (3x)(4x)=7x ?

The solutions to the equation (3x)(4x)=7x are x=0,x= 7/12

Find the zeros of (3x)(4x)=7x

The zeros of (3x)(4x)=7x are x=0,x= 7/12

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(3 x) (4 x) = 7 x

x = 0, x = \frac{7}{12}

Decimal Notation

x = 0, x = 0.58333 \dots

Solution steps

(3 x) (4 x) = 7 x

Move

7 x

to the left side

3 x \cdot 4 x - 7 x = 0

Factor

3 x \cdot 4 x - 7 x : x (12 x - 7)

x (12 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 12 x - 7 = 0

Solve

12 x - 7 = 0 : x = \frac{7}{12}

The solutions to the quadratic equation are:

x = 0, x = \frac{7}{12}

\frac{5 y}{8} - \frac{1}{4} = \frac{y - 1}{2}

\frac{100 - ( 3 \cdot 4 ) ^{2}}{2 ^{2}}

- - 52

(x + 5)^{2} - 9

x^{10} + 1

What are the solutions to the equation (3x)(4x)=7x ?
The solutions to the equation (3x)(4x)=7x are x=0,x= 7/12
Find the zeros of (3x)(4x)=7x
The zeros of (3x)(4x)=7x are x=0,x= 7/12