What are the solutions to the equation 2x^2+5=7 ?

The solutions to the equation 2x^2+5=7 are x=1,x=-1

Find the zeros of 2x^2+5=7

The zeros of 2x^2+5=7 are x=1,x=-1

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2 x^{2} + 5 = 7

x = 1, x = - 1

Solution steps

2 x^{2} + 5 = 7

Move

5

to the right side

2 x^{2} = 2

Divide both sides by

2

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

7 x - 5 = 9

2 p^{3} - p^{2} + 2 p - 1

- \frac{1}{2} x^{2} + 1 = - 39

10 \geq 7 + x - 2 x

1 0^{- 5}

What are the solutions to the equation 2x^2+5=7 ?
The solutions to the equation 2x^2+5=7 are x=1,x=-1
Find the zeros of 2x^2+5=7
The zeros of 2x^2+5=7 are x=1,x=-1