What are the solutions to the equation 0=x^2+2x ?

The solutions to the equation 0=x^2+2x are x=0,x=-2

Find the zeros of 0=x^2+2x

The zeros of 0=x^2+2x are x=0,x=-2

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0 = x^{2} + 2 x

x = 0, x = - 2

Solution steps

0 = x^{2} + 2 x

Switch sides

x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 \cdot 1}, x_{2} = \frac{- 2 - 2}{2 \cdot 1}

x = \frac{- 2 + 2}{2 \cdot 1} : 0

x = \frac{- 2 - 2}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

- 44 > - 2 x - 8 \geq - 8

9 e + 4 = 5 e + 14 + 13 e

x + 4 = 13

(\frac{3}{5}) (- \frac{6}{7}) (- 4)

\frac{2 ( 1 )}{( 1 ) - 2}

What are the solutions to the equation 0=x^2+2x ?
The solutions to the equation 0=x^2+2x are x=0,x=-2
Find the zeros of 0=x^2+2x
The zeros of 0=x^2+2x are x=0,x=-2