What are the solutions to the equation 4x^2+8x+1=0 ?

The solutions to the equation 4x^2+8x+1=0 are x=(-2+sqrt(3))/2 ,x=-(2+sqrt(3))/2

Find the zeros of 4x^2+8x+1=0

The zeros of 4x^2+8x+1=0 are x=(-2+sqrt(3))/2 ,x=-(2+sqrt(3))/2

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4 x^{2} + 8 x + 1 = 0

x = \frac{- 2 + 3}{2}, x = - \frac{2 + 3}{2}

Decimal Notation

x = - 0.13397 \dots, x = - 1.86602 \dots

Solution steps

4 x^{2} + 8 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 1 = 43

x_{1, 2} = \frac{- 8 \pm 4 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4 3}{2 \cdot 4}, x_{2} = \frac{- 8 - 4 3}{2 \cdot 4}

x = \frac{- 8 + 4 3}{2 \cdot 4} : \frac{- 2 + 3}{2}

x = \frac{- 8 - 4 3}{2 \cdot 4} : - \frac{2 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 3}{2}, x = - \frac{2 + 3}{2}

\frac{4 π}{3} - π

(\frac{2}{3})^{\frac{2}{3}} \cdot (\frac{3}{2})^{- \frac{1}{3}}

4 x - 18 \leq - 46

n^{2} = 1 0^{6}

4 x + 36

What are the solutions to the equation 4x^2+8x+1=0 ?
The solutions to the equation 4x^2+8x+1=0 are x=(-2+sqrt(3))/2 ,x=-(2+sqrt(3))/2
Find the zeros of 4x^2+8x+1=0
The zeros of 4x^2+8x+1=0 are x=(-2+sqrt(3))/2 ,x=-(2+sqrt(3))/2