(sqrt(|x+4|^2)-25)(sqrt(x^2)-9)<= 0

Lösung

(∣ x + 4 ∣^{2} - 25) (x^{2} - 9) \leq 0

- 29 \leq x \leq - 9 or 9 \leq x \leq 21

Intervall-Notation

[- 29, - 9] \cup [9, 21]

Schritte zur Lösung

(∣ x + 4 ∣^{2} - 25) (x^{2} - 9) \leq 0

Identifiziere die Intervalle

- 29 \leq x \leq - 9 or 9 \leq x \leq 21

3 (x + 4) = 18

- 4 ∣ 1 - x ∣ < - 16

x - 4 > 3 x + 8

\frac{2}{3} x + 9 < 5

x^{2} - 8 x = 72