What are the solutions to the equation r^2-6r+2=0 ?

The solutions to the equation r^2-6r+2=0 are r=3+sqrt(7),r=3-sqrt(7)

Find the zeros of r^2-6r+2=0

The zeros of r^2-6r+2=0 are r=3+sqrt(7),r=3-sqrt(7)

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r^{2} - 6 r + 2 = 0

r = 3 + 7, r = 3 - 7

Decimal Notation

r = 5.64575 \dots, r = 0.35424 \dots

Solution steps

r^{2} - 6 r + 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 2 = 27

r_{1, 2} = \frac{- ( - 6 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 6 ) + 2 7}{2 \cdot 1}, r_{2} = \frac{- ( - 6 ) - 2 7}{2 \cdot 1}

r = \frac{- ( - 6 ) + 2 7}{2 \cdot 1} : 3 + 7

r = \frac{- ( - 6 ) - 2 7}{2 \cdot 1} : 3 - 7

The solutions to the quadratic equation are:

r = 3 + 7, r = 3 - 7

2 x - 7 = - 1

\frac{2}{\frac{3}{4}}

(3^{2})^{5}

18 = n - 18

\frac{x}{8} + \frac{x}{4} = - 1

What are the solutions to the equation r^2-6r+2=0 ?
The solutions to the equation r^2-6r+2=0 are r=3+sqrt(7),r=3-sqrt(7)
Find the zeros of r^2-6r+2=0
The zeros of r^2-6r+2=0 are r=3+sqrt(7),r=3-sqrt(7)