What are the solutions to the equation (x-4)(x-2)=-1 ?

The solutions to the equation (x-4)(x-2)=-1 are x=3

Find the zeros of (x-4)(x-2)=-1

The zeros of (x-4)(x-2)=-1 are x=3

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(x - 4) (x - 2) = - 1

x = 3

Solution steps

(x - 4) (x - 2) = - 1

Expand

(x - 4) (x - 2) : x^{2} - 6 x + 8

x^{2} - 6 x + 8 = - 1

Move

1

to the left side

x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

x = 3

The solution to the quadratic equation is:

x = 3

(4 x^{4})^{2}

4 m - 5 (3 m + 10) = 126

(n + \frac{1}{2} - 2) \frac{- 1}{2} + \frac{- 1}{2}

\frac{ln ( 2 )}{0.08}

\frac{x + 3}{x ^{2} - 4} - \frac{1}{x + 2} < \frac{2 x}{2 x - x ^{2}}

What are the solutions to the equation (x-4)(x-2)=-1 ?
The solutions to the equation (x-4)(x-2)=-1 are x=3
Find the zeros of (x-4)(x-2)=-1
The zeros of (x-4)(x-2)=-1 are x=3