What are the solutions to the equation x^2+3^2=4^2 ?

The solutions to the equation x^2+3^2=4^2 are x=sqrt(7),x=-sqrt(7)

Find the zeros of x^2+3^2=4^2

The zeros of x^2+3^2=4^2 are x=sqrt(7),x=-sqrt(7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 3^{2} = 4^{2}

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

x^{2} + 3^{2} = 4^{2}

Move

3^{2}

to the right side

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

(- \frac{3}{8})^{2}

1.5 x = 3.45

\frac{24}{2}

lo g_{0.5} (16)

a^{2} + 5 a + 4

What are the solutions to the equation x^2+3^2=4^2 ?
The solutions to the equation x^2+3^2=4^2 are x=sqrt(7),x=-sqrt(7)
Find the zeros of x^2+3^2=4^2
The zeros of x^2+3^2=4^2 are x=sqrt(7),x=-sqrt(7)