What are the solutions to the equation d^2+2d+1=0 ?

The solutions to the equation d^2+2d+1=0 are d=-1

Find the zeros of d^2+2d+1=0

The zeros of d^2+2d+1=0 are d=-1

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d^{2} + 2 d + 1 = 0

d = - 1

Solution steps

d^{2} + 2 d + 1 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

d_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

d = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

d = - 1

The solution to the quadratic equation is:

d = - 1

\frac{4}{3} π (1.95)^{3}

1 - 0.8 x + 0.15 x^{2} = 0

18 = 2 + (y - 6)^{2}

9 x^{2} - 18 x - 27

24 \cdot 4

What are the solutions to the equation d^2+2d+1=0 ?
The solutions to the equation d^2+2d+1=0 are d=-1
Find the zeros of d^2+2d+1=0
The zeros of d^2+2d+1=0 are d=-1