What are the solutions to the equation x^2+x=8 ?

The solutions to the equation x^2+x=8 are x=(-1+sqrt(33))/2 ,x=(-1-sqrt(33))/2

Find the zeros of x^2+x=8

The zeros of x^2+x=8 are x=(-1+sqrt(33))/2 ,x=(-1-sqrt(33))/2

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x^{2} + x = 8

x = \frac{- 1 + 33}{2}, x = \frac{- 1 - 33}{2}

Decimal Notation

x = 2.37228 \dots, x = - 3.37228 \dots

Solution steps

x^{2} + x = 8

Move

8

to the left side

x^{2} + x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 8) = 33

x_{1, 2} = \frac{- 1 \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 33}{2 \cdot 1}, x_{2} = \frac{- 1 - 33}{2 \cdot 1}

x = \frac{- 1 + 33}{2 \cdot 1} : \frac{- 1 + 33}{2}

x = \frac{- 1 - 33}{2 \cdot 1} : \frac{- 1 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 33}{2}, x = \frac{- 1 - 33}{2}

\frac{n ^{3} - n}{n ^{2} - 5 n - 6}

\frac{( x y ) ^{\frac{1}{2}}}{x}

\frac{4}{5} x - 8 = 2

10 x^{2} - 19 x + 6 = 0

x > 3 and x < 2

What are the solutions to the equation x^2+x=8 ?
The solutions to the equation x^2+x=8 are x=(-1+sqrt(33))/2 ,x=(-1-sqrt(33))/2
Find the zeros of x^2+x=8
The zeros of x^2+x=8 are x=(-1+sqrt(33))/2 ,x=(-1-sqrt(33))/2