What are the solutions to the equation -4x=x^2 ?

The solutions to the equation -4x=x^2 are x=0,x=-4

Find the zeros of -4x=x^2

The zeros of -4x=x^2 are x=0,x=-4

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- 4 x = x^{2}

x = 0, x = - 4

Solution steps

- 4 x = x^{2}

Switch sides

x^{2} = - 4 x

Move

4 x

to the left side

x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 \cdot 1}, x_{2} = \frac{- 4 - 4}{2 \cdot 1}

x = \frac{- 4 + 4}{2 \cdot 1} : 0

x = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

1 - \frac{5}{2} x \leq 16

3 < \frac{x}{2} + 1

x^{\frac{2}{3}} x^{\frac{1}{5}}

\frac{r}{8} = 4

4 x + 3 = 2 x - 1

What are the solutions to the equation -4x=x^2 ?
The solutions to the equation -4x=x^2 are x=0,x=-4
Find the zeros of -4x=x^2
The zeros of -4x=x^2 are x=0,x=-4