What are the solutions to the equation 3w^2-w=102 ?

The solutions to the equation 3w^2-w=102 are w=6,w=-17/3

Find the zeros of 3w^2-w=102

The zeros of 3w^2-w=102 are w=6,w=-17/3

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3 w^{2} - w = 102

w = 6, w = - \frac{17}{3}

Decimal Notation

w = 6, w = - 5.66666 \dots

Solution steps

3 w^{2} - w = 102

Move

102

to the left side

3 w^{2} - w - 102 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 102 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 102) = 35

w_{1, 2} = \frac{- ( - 1 ) \pm 35}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- ( - 1 ) + 35}{2 \cdot 3}, w_{2} = \frac{- ( - 1 ) - 35}{2 \cdot 3}

w = \frac{- ( - 1 ) + 35}{2 \cdot 3} : 6

w = \frac{- ( - 1 ) - 35}{2 \cdot 3} : - \frac{17}{3}

The solutions to the quadratic equation are:

w = 6, w = - \frac{17}{3}

x^{2} - 20 x + 19

4 x + 70 = 9 x - 5

192 x^{2} - 16 = 0

\frac{2 π}{\frac{3 π}{4}}

\frac{5}{6} \cdot 5

What are the solutions to the equation 3w^2-w=102 ?
The solutions to the equation 3w^2-w=102 are w=6,w=-17/3
Find the zeros of 3w^2-w=102
The zeros of 3w^2-w=102 are w=6,w=-17/3