What are the solutions to the equation 0=x^2+3x-28 ?

The solutions to the equation 0=x^2+3x-28 are x=4,x=-7

Find the zeros of 0=x^2+3x-28

The zeros of 0=x^2+3x-28 are x=4,x=-7

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0 = x^{2} + 3 x - 28

x = 4, x = - 7

Solution steps

0 = x^{2} + 3 x - 28

Switch sides

x^{2} + 3 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 28) = 11

x_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 11}{2 \cdot 1}, x_{2} = \frac{- 3 - 11}{2 \cdot 1}

x = \frac{- 3 + 11}{2 \cdot 1} : 4

x = \frac{- 3 - 11}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 4, x = - 7

\frac{15}{8} + 4

\frac{2 x}{3} - \frac{x - 1}{2} > \frac{2}{9}

\frac{1}{2} \cdot \frac{π}{2}

12 x^{2} + 6 = 0

- 3 x - 6 \geq - 5

What are the solutions to the equation 0=x^2+3x-28 ?
The solutions to the equation 0=x^2+3x-28 are x=4,x=-7
Find the zeros of 0=x^2+3x-28
The zeros of 0=x^2+3x-28 are x=4,x=-7