What are the solutions to the equation 9z^2+24z+16=0 ?

The solutions to the equation 9z^2+24z+16=0 are z=-4/3

Find the zeros of 9z^2+24z+16=0

The zeros of 9z^2+24z+16=0 are z=-4/3

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9 z^{2} + 24 z + 16 = 0

z = - \frac{4}{3}

Decimal Notation

z = - 1.33333 \dots

Solution steps

9 z^{2} + 24 z + 16 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 9 \cdot 16}{2 \cdot 9}

2 4^{2} - 4 \cdot 9 \cdot 16 = 0

z_{1, 2} = \frac{- 24 \pm 0}{2 \cdot 9}

z = \frac{- 24}{2 \cdot 9}

\frac{- 24}{2 \cdot 9} = - \frac{4}{3}

z = - \frac{4}{3}

The solution to the quadratic equation is:

z = - \frac{4}{3}

6 (4 + 5 v) - 3 = - 57

2 x + 8 - 9 x = 7 + 2 x - 2

x^{2} + 0.7 5^{2} = 1^{2}

(x - 4)^{(2)} + (x - 2)^{(2)} = x^{(2)}

\frac{\frac{2}{3}}{4}

What are the solutions to the equation 9z^2+24z+16=0 ?
The solutions to the equation 9z^2+24z+16=0 are z=-4/3
Find the zeros of 9z^2+24z+16=0
The zeros of 9z^2+24z+16=0 are z=-4/3