What are the solutions to the equation -4a^2-28a-40=0 ?

The solutions to the equation -4a^2-28a-40=0 are a=-5,a=-2

Find the zeros of -4a^2-28a-40=0

The zeros of -4a^2-28a-40=0 are a=-5,a=-2

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- 4 a^{2} - 28 a - 40 = 0

a = - 5, a = - 2

Solution steps

- 4 a^{2} - 28 a - 40 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 ( - 4 ) ( - 40 )}{2 ( - 4 )}

(- 28)^{2} - 4 (- 4) (- 40) = 12

a_{1, 2} = \frac{- ( - 28 ) \pm 12}{2 ( - 4 )}

Separate the solutions

a_{1} = \frac{- ( - 28 ) + 12}{2 ( - 4 )}, a_{2} = \frac{- ( - 28 ) - 12}{2 ( - 4 )}

a = \frac{- ( - 28 ) + 12}{2 ( - 4 )} : - 5

a = \frac{- ( - 28 ) - 12}{2 ( - 4 )} : - 2

The solutions to the quadratic equation are:

a = - 5, a = - 2

x^{5} - 64 x \leq 0

8 - x = 6

4 (x + 2) \leq 0

8 + 5 x = - 2

\frac{1}{2} + \frac{1}{6}

What are the solutions to the equation -4a^2-28a-40=0 ?
The solutions to the equation -4a^2-28a-40=0 are a=-5,a=-2
Find the zeros of -4a^2-28a-40=0
The zeros of -4a^2-28a-40=0 are a=-5,a=-2