What is -x^3+2x^2+13x+10>0 ?

The solution to -x^3+2x^2+13x+10>0 is x<-2\lor-1<x<5

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-x^3+2x^2+13x+10>0

- x^{3} + 2 x^{2} + 13 x + 10 > 0

x < - 2 or - 1 < x < 5

Interval Notation

(- \infty, - 2) \cup (- 1, 5)

Solution steps

- x^{3} + 2 x^{2} + 13 x + 10 > 0

Factor

- x^{3} + 2 x^{2} + 13 x + 10 : - (x + 1) (x + 2) (x - 5)

- (x + 1) (x + 2) (x - 5) > 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x + 1) (x + 2) (x - 5)) (- 1) < 0 \cdot (- 1)

Simplify

(x + 1) (x + 2) (x - 5) < 0

Identify the intervals

x < - 2 or - 1 < x < 5

- 5 + 6 ∣ 2 x + 2 ∣ = 7

x + 4 = 5

\frac{ln ( \frac{1}{2} )}{1620}

177147 = 54 ln (3) (2) + b

- 6 x + 5 x = - 4

What is -x^3+2x^2+13x+10>0 ?
The solution to -x^3+2x^2+13x+10>0 is x<-2\lor-1<x<5