-3/2 x>=-6

Solution

- \frac{3}{2} x \geq - 6

x \leq 4

Interval Notation

(- \infty, 4]

Solution steps

- \frac{3}{2} x \geq - 6

Multiply both sides by

- 1

\frac{3}{2} x \leq 6

Multiply both sides by

2

3 x \leq 12

Divide both sides by

3

x \leq 4

(625 x^{6})^{\frac{3}{4}}

4 x + 2 x + 6 = 90

5 x^{2} + 3 x = 92

(- 2 h^{5}) (4 h^{- 3})

\frac{( \frac{\frac{a}{b}}{\frac{c}{d}} )}{\frac{e}{f}}