What are the solutions to the equation 0=88t-16t^2 ?

The solutions to the equation 0=88t-16t^2 are t=0,t= 11/2

Find the zeros of 0=88t-16t^2

The zeros of 0=88t-16t^2 are t=0,t= 11/2

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0 = 88 t - 16 t^{2}

t = 0, t = \frac{11}{2}

Decimal Notation

t = 0, t = 5.5

Solution steps

0 = 88 t - 16 t^{2}

Switch sides

88 t - 16 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 88 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 88 \pm 8 8 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

8 8^{2} - 4 (- 16) \cdot 0 = 88

t_{1, 2} = \frac{- 88 \pm 88}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 88 + 88}{2 ( - 16 )}, t_{2} = \frac{- 88 - 88}{2 ( - 16 )}

t = \frac{- 88 + 88}{2 ( - 16 )} : 0

t = \frac{- 88 - 88}{2 ( - 16 )} : \frac{11}{2}

The solutions to the quadratic equation are:

t = 0, t = \frac{11}{2}

(\frac{e}{s - 2})^{- 2 s}

x^{2} - 6 x - 9 = - 5 x - 3

4 x^{2} = 11 x + 45

m - 5 = - 10

4 (4 + 2 m) = 48

What are the solutions to the equation 0=88t-16t^2 ?
The solutions to the equation 0=88t-16t^2 are t=0,t= 11/2
Find the zeros of 0=88t-16t^2
The zeros of 0=88t-16t^2 are t=0,t= 11/2