What are the solutions to the equation 36x^2-21=0 ?

The solutions to the equation 36x^2-21=0 are x=(sqrt(7))/(2sqrt(3)),x=-(sqrt(7))/(2sqrt(3))

Find the zeros of 36x^2-21=0

The zeros of 36x^2-21=0 are x=(sqrt(7))/(2sqrt(3)),x=-(sqrt(7))/(2sqrt(3))

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36 x^{2} - 21 = 0

x = \frac{7}{2 3}, x = - \frac{7}{2 3}

Decimal Notation

x = 0.76376 \dots, x = - 0.76376 \dots

Solution steps

36 x^{2} - 21 = 0

Move

21

to the right side

36 x^{2} = 21

Divide both sides by

36

x^{2} = \frac{7}{12}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{12}, x = - \frac{7}{12}

\frac{7}{12} = \frac{7}{2 3}

- \frac{7}{12} = - \frac{7}{2 3}

x = \frac{7}{2 3}, x = - \frac{7}{2 3}

2 x^{2} - 7 x + 3 > 0

u 1 + x^{2} + 1 - (ux)^{2}

x^{2} - 5 x - 126

3 x^{2} - 1 x = 1 x + 8

6 x = 3

What are the solutions to the equation 36x^2-21=0 ?
The solutions to the equation 36x^2-21=0 are x=(sqrt(7))/(2sqrt(3)),x=-(sqrt(7))/(2sqrt(3))
Find the zeros of 36x^2-21=0
The zeros of 36x^2-21=0 are x=(sqrt(7))/(2sqrt(3)),x=-(sqrt(7))/(2sqrt(3))