What are the solutions to the equation x(x+2)=5 ?

The solutions to the equation x(x+2)=5 are x=-1+sqrt(6),x=-1-sqrt(6)

Find the zeros of x(x+2)=5

The zeros of x(x+2)=5 are x=-1+sqrt(6),x=-1-sqrt(6)

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x (x + 2) = 5

x = - 1 + 6, x = - 1 - 6

Decimal Notation

x = 1.44948 \dots, x = - 3.44948 \dots

Solution steps

x (x + 2) = 5

Expand

x (x + 2) : x^{2} + 2 x

x^{2} + 2 x = 5

Move

5

to the left side

x^{2} + 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 5) = 26

x_{1, 2} = \frac{- 2 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 6}{2 \cdot 1}

x = \frac{- 2 + 2 6}{2 \cdot 1} : - 1 + 6

x = \frac{- 2 - 2 6}{2 \cdot 1} : - 1 - 6

The solutions to the quadratic equation are:

x = - 1 + 6, x = - 1 - 6

4 x^{2} - 4 x + 1 \leq 0

- 2 (4 a - 3) = 4 (- a + 2)

m^{5} n^{2} + m^{6} n^{3}

- 12 = - 2 a + 6

lo g_{10} (8256) = x

What are the solutions to the equation x(x+2)=5 ?
The solutions to the equation x(x+2)=5 are x=-1+sqrt(6),x=-1-sqrt(6)
Find the zeros of x(x+2)=5
The zeros of x(x+2)=5 are x=-1+sqrt(6),x=-1-sqrt(6)