What is (15c)/(12(d-3))*(21d)/(6c) ?

The solution to (15c)/(12(d-3))*(21d)/(6c) is (35d)/(8(d-3))

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simplify (15c)/(12(d-3))*(21d)/(6c)

simplify

\frac{15 c}{12 ( d - 3 )} \cdot \frac{21 d}{6 c}

\frac{35 d}{8 ( d - 3 )}

Solution steps

\frac{15 c}{12 ( d - 3 )} \cdot \frac{21 d}{6 c}

Cancel

\frac{15 c}{12 ( d - 3 )} : \frac{5 c}{4 ( d - 3 )}

= \frac{5 c}{4 ( d - 3 )} \cdot \frac{21 d}{6 c}

Cancel

\frac{21 d}{6 c} : \frac{7 d}{2 c}

= \frac{5 c}{4 ( d - 3 )} \cdot \frac{7 d}{2 c}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{5 c \cdot 7 d}{4 ( d - 3 ) \cdot 2 c}

Cancel the common factor:

c

= \frac{5 \cdot 7 d}{4 ( d - 3 ) \cdot 2}

Multiply the numbers:

5 \cdot 7 = 35

= \frac{35 d}{4 ( d - 3 ) \cdot 2}

Multiply the numbers:

4 \cdot 2 = 8

= \frac{35 d}{8 ( d - 3 )}

8 x^{3} - 64 y^{3}

30 n^{3} - 12 n^{2} - 18 n

(8 x^{4} y^{- 3}) (\frac{1}{2} x^{- 5} y^{2})

\frac{6}{x - 4} \leq 2

3 x^{2} - 3 x - 5 = 0

What is (15c)/(12(d-3))*(21d)/(6c) ?
The solution to (15c)/(12(d-3))*(21d)/(6c) is (35d)/(8(d-3))