What is (x-2)(x+1)(2x+1)(x-3)<0 ?

The solution to (x-2)(x+1)(2x+1)(x-3)<0 is -1<x<-1/2 \lor 2<x<3

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(x-2)(x+1)(2x+1)(x-3)<0

(x - 2) (x + 1) (2 x + 1) (x - 3) < 0

- 1 < x < - \frac{1}{2} or 2 < x < 3

Interval Notation

(- 1, - \frac{1}{2}) \cup (2, 3)

Decimal Notation

- 1 < x < - 0.5 or 2 < x < 3

Solution steps

(x - 2) (x + 1) (2 x + 1) (x - 3) < 0

Identify the intervals

- 1 < x < - \frac{1}{2} or 2 < x < 3

\frac{2}{i ^{15} - i ^{- 15}}

y + 3 = - y + 9

5 w^{2} + 13 w - 6

3 x^{2} + 7 - 10 x = 0

7 x^{2} + 28 x - 35

What is (x-2)(x+1)(2x+1)(x-3)<0 ?
The solution to (x-2)(x+1)(2x+1)(x-3)<0 is -1<x<-1/2 \lor 2<x<3