What are the solutions to the equation 192-75z^2=0 ?

The solutions to the equation 192-75z^2=0 are z= 8/5 ,z=-8/5

Find the zeros of 192-75z^2=0

The zeros of 192-75z^2=0 are z= 8/5 ,z=-8/5

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192 - 75 z^{2} = 0

z = \frac{8}{5}, z = - \frac{8}{5}

Solution steps

192 - 75 z^{2} = 0

Move

192

to the right side

- 75 z^{2} = - 192

Divide both sides by

- 75

z^{2} = \frac{64}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = \frac{64}{25}, z = - \frac{64}{25}

\frac{64}{25} = \frac{8}{5}

- \frac{64}{25} = - \frac{8}{5}

z = \frac{8}{5}, z = - \frac{8}{5}

8 n^{2} + 68 n + 84

\frac{1}{1 + 3}

2 x^{2} + 2 x - 24

\frac{\frac{2}{b} + \frac{2}{a}}{\frac{2}{ab}}

\frac{4}{9} (- \frac{9}{4})

What are the solutions to the equation 192-75z^2=0 ?
The solutions to the equation 192-75z^2=0 are z= 8/5 ,z=-8/5
Find the zeros of 192-75z^2=0
The zeros of 192-75z^2=0 are z= 8/5 ,z=-8/5