What is (1/x+1/y)/(1/x-1/y) ?

The solution to (1/x+1/y)/(1/x-1/y) is (y+x)/(y-x)

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simplify (1/x+1/y)/(1/x-1/y)

simplify

\frac{\frac{1}{x} + \frac{1}{y}}{\frac{1}{x} - \frac{1}{y}}

\frac{y + x}{y - x}

Solution steps

\frac{\frac{1}{x} + \frac{1}{y}}{\frac{1}{x} - \frac{1}{y}}

Join

\frac{1}{x} + \frac{1}{y} : \frac{y + x}{x y}

= \frac{\frac{y + x}{x y}}{\frac{1}{x} - \frac{1}{y}}

Join

\frac{1}{x} - \frac{1}{y} : \frac{y - x}{x y}

= \frac{\frac{y + x}{x y}}{\frac{y - x}{x y}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( y + x ) x y}{x y ( y - x )}

Cancel

\frac{( y + x ) x y}{x y ( y - x )} : \frac{y + x}{y - x}

= \frac{y + x}{y - x}

6 (v - 5) - 2 v = 2

(\frac{1}{2}) (\frac{1}{2})

1 0^{5 l o g_{10} (5)}

(\frac{8}{27})^{\frac{2}{3}}

What is (1/x+1/y)/(1/x-1/y) ?
The solution to (1/x+1/y)/(1/x-1/y) is (y+x)/(y-x)