What are the solutions to the equation 11x^2+5x+2=0 ?

The solutions to the equation 11x^2+5x+2=0 are x=-5/22+i(3sqrt(7))/(22),x=-5/22-i(3sqrt(7))/(22)

Find the zeros of 11x^2+5x+2=0

The zeros of 11x^2+5x+2=0 are x=-5/22+i(3sqrt(7))/(22),x=-5/22-i(3sqrt(7))/(22)

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11 x^{2} + 5 x + 2 = 0

x = - \frac{5}{22} + i \frac{3 7}{22}, x = - \frac{5}{22} - i \frac{3 7}{22}

Solution steps

11 x^{2} + 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 11 \cdot 2}{2 \cdot 11}

Simplify

5^{2} - 4 \cdot 11 \cdot 2 : 37 i

x_{1, 2} = \frac{- 5 \pm 3 7 i}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- 5 + 3 7 i}{2 \cdot 11}, x_{2} = \frac{- 5 - 3 7 i}{2 \cdot 11}

x = \frac{- 5 + 3 7 i}{2 \cdot 11} : - \frac{5}{22} + i \frac{3 7}{22}

x = \frac{- 5 - 3 7 i}{2 \cdot 11} : - \frac{5}{22} - i \frac{3 7}{22}

The solutions to the quadratic equation are:

x = - \frac{5}{22} + i \frac{3 7}{22}, x = - \frac{5}{22} - i \frac{3 7}{22}

x^{2} + 5 x - 7 \geq 0

- \frac{12}{7} = - 6 y

\frac{π}{2} + \frac{3 π}{2}

x^{2} + x^{2} = 36

\frac{3 ^{3}}{3 !}

What are the solutions to the equation 11x^2+5x+2=0 ?
The solutions to the equation 11x^2+5x+2=0 are x=-5/22+i(3sqrt(7))/(22),x=-5/22-i(3sqrt(7))/(22)
Find the zeros of 11x^2+5x+2=0
The zeros of 11x^2+5x+2=0 are x=-5/22+i(3sqrt(7))/(22),x=-5/22-i(3sqrt(7))/(22)