What are the solutions to the equation 7x^2+28=28x ?

The solutions to the equation 7x^2+28=28x are x=2

Find the zeros of 7x^2+28=28x

The zeros of 7x^2+28=28x are x=2

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7 x^{2} + 28 = 28 x

x = 2

Solution steps

7 x^{2} + 28 = 28 x

Move

28 x

to the left side

7 x^{2} + 28 - 28 x = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} - 28 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 7 \cdot 28}{2 \cdot 7}

(- 28)^{2} - 4 \cdot 7 \cdot 28 = 0

x_{1, 2} = \frac{- ( - 28 ) \pm 0}{2 \cdot 7}

x = \frac{- ( - 28 )}{2 \cdot 7}

\frac{- ( - 28 )}{2 \cdot 7} = 2

x = 2

The solution to the quadratic equation is:

x = 2

∣ 4 x + 13 ∣ < 3

- 2 x \geq - 10

12 = 0.00006 n^{2} + 0.012 n + 7.884

14 + x \leq 26

(3 x^{3} y^{4}) (4 x y^{5})

What are the solutions to the equation 7x^2+28=28x ?
The solutions to the equation 7x^2+28=28x are x=2
Find the zeros of 7x^2+28=28x
The zeros of 7x^2+28=28x are x=2