What is -2(4y-7)+y>= 2y-(-5+y) ?

The solution to -2(4y-7)+y>= 2y-(-5+y) is y<= 9/8

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-2(4y-7)+y>= 2y-(-5+y)

- 2 (4 y - 7) + y \geq 2 y - (- 5 + y)

y \leq \frac{9}{8}

Solution steps

- 2 (4 y - 7) + y \geq 2 y - (- 5 + y)

Expand

- 2 (4 y - 7) + y : - 7 y + 14

Expand

2 y - (- 5 + y) : y + 5

- 7 y + 14 \geq y + 5

Move

14

to the right side

- 7 y \geq y - 9

Move

y

to the left side

- 8 y \geq - 9

Multiply both sides by

- 1

8 y \leq 9

Divide both sides by

8

y \leq \frac{9}{8}

56 \cdot 9 \div 14 \cdot \frac{1}{3}

x^{2} \geq x

(x^{\frac{1}{2}})^{- 1}

144 b^{2} - 25 c^{2}

h = 17 + \frac{- 18}{6}

What is -2(4y-7)+y>= 2y-(-5+y) ?
The solution to -2(4y-7)+y>= 2y-(-5+y) is y<= 9/8