What are the solutions to the equation 7v^2+1=29 ?

The solutions to the equation 7v^2+1=29 are v=2,v=-2

Find the zeros of 7v^2+1=29

The zeros of 7v^2+1=29 are v=2,v=-2

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7 v^{2} + 1 = 29

v = 2, v = - 2

Solution steps

7 v^{2} + 1 = 29

Move

1

to the right side

7 v^{2} = 28

Divide both sides by

7

v^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = 4, v = - 4

4 = 2

- 4 = - 2

v = 2, v = - 2

a (b - c) + d (c - b)

(8 + 3 i)^{2}

x^{2} + 5 x - 14 = 0

2 m - m^{2}

343 z^{3} + 27 x^{3}

What are the solutions to the equation 7v^2+1=29 ?
The solutions to the equation 7v^2+1=29 are v=2,v=-2
Find the zeros of 7v^2+1=29
The zeros of 7v^2+1=29 are v=2,v=-2