What are the solutions to the equation 3(x+4)^2+15(x+4)-18=0 ?

The solutions to the equation 3(x+4)^2+15(x+4)-18=0 are x=-3,x=-10

Find the zeros of 3(x+4)^2+15(x+4)-18=0

The zeros of 3(x+4)^2+15(x+4)-18=0 are x=-3,x=-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (x + 4)^{2} + 15 (x + 4) - 18 = 0

x = - 3, x = - 10

Solution steps

3 (x + 4)^{2} + 15 (x + 4) - 18 = 0

Expand

3 (x + 4)^{2} + 15 (x + 4) - 18 : 3 x^{2} + 39 x + 90

3 x^{2} + 39 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 39 \pm 3 9 ^{2} - 4 \cdot 3 \cdot 90}{2 \cdot 3}

3 9^{2} - 4 \cdot 3 \cdot 90 = 21

x_{1, 2} = \frac{- 39 \pm 21}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 39 + 21}{2 \cdot 3}, x_{2} = \frac{- 39 - 21}{2 \cdot 3}

x = \frac{- 39 + 21}{2 \cdot 3} : - 3

x = \frac{- 39 - 21}{2 \cdot 3} : - 10

The solutions to the quadratic equation are:

x = - 3, x = - 10

s^{2} - 9 s - 10 = 0

4 n^{8} - 20 n^{4} + 25

x^{2} - 5 x + 1 = 0

(4 - 3 i) + (2 i - 8)

- 2 (x + 1) < 2

What are the solutions to the equation 3(x+4)^2+15(x+4)-18=0 ?
The solutions to the equation 3(x+4)^2+15(x+4)-18=0 are x=-3,x=-10
Find the zeros of 3(x+4)^2+15(x+4)-18=0
The zeros of 3(x+4)^2+15(x+4)-18=0 are x=-3,x=-10