What are the solutions to the equation 4x^2-8x=-3 ?

The solutions to the equation 4x^2-8x=-3 are x= 3/2 ,x= 1/2

Find the zeros of 4x^2-8x=-3

The zeros of 4x^2-8x=-3 are x= 3/2 ,x= 1/2

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4 x^{2} - 8 x = - 3

x = \frac{3}{2}, x = \frac{1}{2}

Solution steps

4 x^{2} - 8 x = - 3

Move

3

to the left side

4 x^{2} - 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 \cdot 3 = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4}{2 \cdot 4} : \frac{3}{2}

x = \frac{- ( - 8 ) - 4}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = \frac{1}{2}

- 3 ∣ 3 - 3 x ∣ - 2 \leq - 29

∣ z + 25 ∣ = 5

9 - 2 x = 15

- 9 (x - 5) + 9 \leq 3 x + 42

\frac{3 w + 5}{4} \geq 2 w

What are the solutions to the equation 4x^2-8x=-3 ?
The solutions to the equation 4x^2-8x=-3 are x= 3/2 ,x= 1/2
Find the zeros of 4x^2-8x=-3
The zeros of 4x^2-8x=-3 are x= 3/2 ,x= 1/2