What is 1/(a^2b^{-3)}(a^2b^{-3})^{-1} ?

The solution to 1/(a^2b^{-3)}(a^2b^{-3})^{-1} is (b^6)/(a^4)

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simplify 1/(a^2b^{-3)}(a^2b^{-3})^{-1}

simplify

\frac{1}{a ^{2} b ^{- 3}} (a^{2} b^{- 3})^{- 1}

\frac{b ^{6}}{a ^{4}}

Solution steps

\frac{1}{a ^{2} b ^{- 3}} (a^{2} b^{- 3})^{- 1}

Simplify

(a^{2} b^{- 3})^{- 1} : \frac{b ^{3}}{a ^{2}}

= \frac{1}{a ^{2} b ^{- 3}} \cdot \frac{b ^{3}}{a ^{2}}

Simplify

\frac{1}{a ^{2} b ^{- 3}} : \frac{b ^{3}}{a ^{2}}

= \frac{b ^{3}}{a ^{2}} \cdot \frac{b ^{3}}{a ^{2}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{b ^{3} b ^{3}}{a ^{2} a ^{2}}

Simplify

b^{3} b^{3} : b^{6}

= \frac{b ^{6}}{a ^{2} a ^{2}}

Simplify

a^{2} a^{2} : a^{4}

= \frac{b ^{6}}{a ^{4}}

2 (3 - 5 x) > 18 - 8 x

\frac{1}{15}

- x^{2} + (8 \cdot 1 0^{- 6}) x = 4.17 x 1 0^{- 12}

2 x^{2} y - 6 x y^{2} + 3 x y

\frac{c ^{- 2} d ^{- 1}}{c ^{7} d ^{- 2}}

What is 1/(a^2b^{-3)}(a^2b^{-3})^{-1} ?
The solution to 1/(a^2b^{-3)}(a^2b^{-3})^{-1} is (b^6)/(a^4)