What are the solutions to the equation quadraticformula (x-5)(x-2)=0 ?

The solutions to the equation quadraticformula (x-5)(x-2)=0 are x=5,x=2

Find the zeros of quadraticformula (x-5)(x-2)=0

The zeros of quadraticformula (x-5)(x-2)=0 are x=5,x=2

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(x - 5) (x - 2) = 0

x = 5, x = 2

Solution steps

(x - 5) (x - 2) = 0

Expand

(x - 5) (x - 2) : x^{2} - 7 x + 10

x^{2} - 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

x_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

x = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

x = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 5, x = 2

\frac{( 4 ^{11} )}{( 4 ^{- 8} )}

\frac{( 252 )}{3}

54%

x, (x + 5 \frac{1}{2}) \cdot 0.75 = \frac{5}{8}

60/2 \frac{2}{3}

What are the solutions to the equation quadraticformula (x-5)(x-2)=0 ?
The solutions to the equation quadraticformula (x-5)(x-2)=0 are x=5,x=2
Find the zeros of quadraticformula (x-5)(x-2)=0
The zeros of quadraticformula (x-5)(x-2)=0 are x=5,x=2