What is cramer 1.9v=3.2t,1.9t-2.1v=2 ?

The solution to cramer 1.9v=3.2t,1.9t-2.1v=2 is v=-(6.4)/(3.11),t=-(3.8)/(3.11)

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Solve Using a Matrix with Cramer's Rule 1.9v=3.2t , 1.9t-2.1v=2

1.9 v = 3.2 t, 1.9 t - 2.1 v = 2

v = - \frac{6.4}{3.11}, t = - \frac{3.8}{3.11}

Solution steps

[1.9 v = 3.2 t 1.9 t - 2.1 v = 2]

Arrange equation variables for elimination

[1.9 v - 3.2 t = 0 - 2.1 v + 1.9 t = 2]

Matrix of Coefficients

M = (1.9 - 2.1 - 3.2 1.9)

Answers column:

(02)

Replace the

v

-column values with the answer-column values

M_{v} = (02 - 3.2 1.9)

Replace the

t

-column values with the answer-column values

M_{t} = (1.9 - 2.1 02)

D = - 3.11

D_{v} = 6.4

D_{t} = 3.8

Solve by using Cramer Rule

x = \frac{D _{x}}{D}, y = \frac{D _{y}}{D}, z = \frac{D _{z}}{D}

v = \frac{D _{v}}{D} = \frac{6.4}{- 3.11}

Simplify

v = - \frac{6.4}{3.11}

t = \frac{D _{t}}{D} = \frac{3.8}{- 3.11}

Simplify

t = - \frac{3.8}{3.11}

The solutions to the system of equations are:

v = - \frac{6.4}{3.11}, t = - \frac{3.8}{3.11}

What is cramer 1.9v=3.2t,1.9t-2.1v=2 ?
The solution to cramer 1.9v=3.2t,1.9t-2.1v=2 is v=-(6.4)/(3.11),t=-(3.8)/(3.11)