What are the solutions to the equation quadraticformula 5x^2+9x=-4 ?

The solutions to the equation quadraticformula 5x^2+9x=-4 are x=-4/5 ,x=-1

Find the zeros of quadraticformula 5x^2+9x=-4

The zeros of quadraticformula 5x^2+9x=-4 are x=-4/5 ,x=-1

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5 x^{2} + 9 x = - 4

x = - \frac{4}{5}, x = - 1

Decimal

x = - 0.8, x = - 1

Solution steps

5 x^{2} + 9 x = - 4

Move

4

to the left side

5 x^{2} + 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

9^{2} - 4 \cdot 5 \cdot 4 = 1

x_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 9 + 1}{2 \cdot 5}, x_{2} = \frac{- 9 - 1}{2 \cdot 5}

x = \frac{- 9 + 1}{2 \cdot 5} : - \frac{4}{5}

x = \frac{- 9 - 1}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

x = - \frac{4}{5}, x = - 1

x, ∣ 2 x - 5 ∣ = 8

x, 0.5 + x = 1.5 - x

- 15 - 27

(3 a + 5 a^{2} b) (3 a - 5 a^{2} b)

544

What are the solutions to the equation quadraticformula 5x^2+9x=-4 ?
The solutions to the equation quadraticformula 5x^2+9x=-4 are x=-4/5 ,x=-1
Find the zeros of quadraticformula 5x^2+9x=-4
The zeros of quadraticformula 5x^2+9x=-4 are x=-4/5 ,x=-1